b^3+20b=9b^2

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Solution for b^3+20b=9b^2 equation:


Simplifying
b3 + 20b = 9b2

Reorder the terms:
20b + b3 = 9b2

Solving
20b + b3 = 9b2

Solving for variable 'b'.

Reorder the terms:
20b + -9b2 + b3 = 9b2 + -9b2

Combine like terms: 9b2 + -9b2 = 0
20b + -9b2 + b3 = 0

Factor out the Greatest Common Factor (GCF), 'b'.
b(20 + -9b + b2) = 0

Factor a trinomial.
b((4 + -1b)(5 + -1b)) = 0

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Subproblem 3

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {0, 4, 5}

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